xmppAcceptSubscription()
Accepts an XMPP request of type "subscriptionRequest".
Synopsis
int xmppAcceptSubscription(int clientId, string jid [, string
reason]);
Parameter
| Parameter | Description |
|---|---|
| clientId | A unique ID for this client channel. The function xmppOpen() returns the client id. |
| jid | Jabber ID such as winccoa.etm@jabber.at of the user who sent the request. |
| reason | Reason why the request was accepted. |
Return Value
Returns 0 when the function was successfully executed or -1 in case of errors
Errors
Errors can be queried via getLastError().
Description
Accepts an XMPP request of type "subscriptionRequest".
The following example accepts an XMPP request of type "subscriptionRequest".
Anmerkung: You have to replace the code:
p =
xmppOpen("winccoa.etm@jabber.at","123677", "callback", m); DebugN("xmppOpen:",
p); by your own user and password. This code is an example!#uses "CtrlXmpp"
int p;
main(mapping event)
{
mapping m;
int port;
string host;
string resource;
bool autoAcceptSubscriptions = FALSE;
/*When set to FALSE, a message of type "subscriptionRequest" is received, which must be
either accepted via xmppAcceptSubscription() or refused via xmppRefuseSubscription().*/
string logging;
m["host"]= host;
m["port"] = port;
m["resource"] = resource;
m["autoAcceptSubscriptions"] = autoAcceptSubscriptions;
m["logging"] = "send";
p = xmppOpen("winccoa.etm@jabber.at","123677", "callback", m);
DebugN("xmppOpen:", p);
}
void callback(mapping message) /* Received message output */
{
int l = xmppAcceptSubscription(p, "maxMuster@jabber.at","Accepted subscription");
DebugN("Accepted subscription:", l);
/*You have to receive a request from the user "maxMuster@jabber.at" in order to accept the request by using this example */
}Assignment
Availability
CTRL
