TCP connection type raw

[IBRAHIMALALI]

Good day all ,

I have a question regarding tcp socket, in wincc the function tcpopen doesnt include a parameter to determine the socket type ,as you see below :

"int tcpOpen(string host, unsigned port [, time timeout]);"

Is there a way to use the wincc function as the below c# function which includes the socket type :

" IPAddress LoginIP = IPAddress.Parse("192.168.104.3");
Socket Socket = new Socket(AddressFamily.InterNetwork, SocketType.Raw, ProtocolType.Tcp);
Socket.Connect(LoginIP, 8020); "



Regards and thank you

[mkoller]

There is no such option. tcpOpen() always opens a stream socket

[IBRAHIMALALI]

But the message server that we are dealing with only accepts tcp socket type raw .
Please do you suggest any method to open channel from wincc , as what we get when using the top open is the access is accepted but no more , meaning no data transactions.

Regards and sorry for the inconvenience

[leoknipp]

You can maybe implement a C++ extension (loaded in a CTRL manager) or a WinCC OA API manager to open a TCP connection with the options needed.

Best Regards
Leopold Knipp
Senior Support Specialist

[Asem Bani Salameh]

Good day ,
Is there any other suggestion?
Has anyone here implemented such kind of solution to share with me .

Thank you all

[Gertjan van Schijndel]

Besides using the API (or ordering a feature request) there are no other solutions possible.

Since you seem to have C# experience, you could create a C# WinCC OA API manager. If C++ is not a problem you could create a control extension.