thread funtion is broken?

[kilianvp]

i took the example for threads form the help. The Problem is that booth threads have the same ID

Code: Select all

void myFunction()
{
int a;
for (a = 0; a < 10; a++)
DebugN(getThreadId(), a);
}
main()
{
startThread("myFunction");
/*startet einen neuen Thread der Funktion "myFunction"*/
startThread("myFunction"); 
/*startet parallel einen 2.Thread wobei jeder Thread für sich von 0 bis
9 zählt und die jeweilige Threadnummer ausgibt*/
}

but the output is:

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WCCOAui1:[1][0]
WCCOAui1:[1][1]
WCCOAui1:[1][2]
WCCOAui1:[1][3]
WCCOAui1:[1][4]
WCCOAui1:[1][5]
WCCOAui1:[1][6]
WCCOAui1:[1][7]
WCCOAui1:[1][8]
WCCOAui1:[1][9]
WCCOAui1:[1][0]
WCCOAui1:[1][1]
WCCOAui1:[1][2]
WCCOAui1:[1][3]
WCCOAui1:[1][4]
WCCOAui1:[1][5]
WCCOAui1:[1][6]
WCCOAui1:[1][7]
WCCOAui1:[1][8]
WCCOAui1:[1][9]

however if i add another Thread the output is:

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WCCOAui1:[1][0]
WCCOAui1:[1][1]
WCCOAui1:[1][2]
WCCOAui1:[1][3]
WCCOAui1:[1][4]
WCCOAui1:[1][5]
WCCOAui1:[1][6]
WCCOAui1:[1][7]
WCCOAui1:[1][8]
WCCOAui1:[1][9]
WCCOAui1:[2][0]
WCCOAui1:[2][1]
WCCOAui1:[2][2]
WCCOAui1:[2][3]
WCCOAui1:[2][4]
WCCOAui1:[2][5]
WCCOAui1:[2][6]
WCCOAui1:[2][7]
WCCOAui1:[2][8]
WCCOAui1:[2][9]
WCCOAui1:[1][0]
WCCOAui1:[1][1]
WCCOAui1:[1][2]
WCCOAui1:[1][3]
WCCOAui1:[1][4]
WCCOAui1:[1][5]
WCCOAui1:[1][6]
WCCOAui1:[1][7]
WCCOAui1:[1][8]
WCCOAui1:[1][9]

[mkoller]

The first thread is finishing its work before the new thread starts. That means, the first thread gets id 1, finishes, therefore frees number 1, then the
next thread starts having again number 1.
When you change the code in myFunction a bit, then you'll see both threads running in parallel.
e.g. { delay(0,1); DebugN(getThreadId(), a); }

[kilianvp]

thank you